98. 验证二叉搜索树
- 题号:98
- 来源:LeetCode
- 难度:中等
- 标签:
树二叉搜索树DFS - 语言:TypeScript
- 解法:1 个
- 作者:lmliheng
- 最近更新:2026-09-27
TypeScript · O(n) 时间 · O(n) 空间 · 更新于 2026-09-27
中序遍历收集后判严格递增,未提前返回
typescript
/**
* @difficulty medium
* @tags 树,二叉搜索树,DFS
* @time O(n)
* @space O(n)
* @note 中序遍历收集后判严格递增,未提前返回
* @98. 验证二叉搜索树
*/
class TreeNode {
val: number;
left: TreeNode | null;
right: TreeNode | null;
constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {
this.val = (val === undefined ? 0 : val)
this.left = (left === undefined ? null : left)
this.right = (right === undefined ? null : right)
}
}
let root: TreeNode = new TreeNode(4, new TreeNode(2), new TreeNode(5, null, new TreeNode(6)))
// new TreeNode(5, new TreeNode(1), new TreeNode(4,new TreeNode(3),new TreeNode(6)))
console.log(root)
if (!root) { console.log(true) }
let arr: number[] = []
let res: boolean = true
const dfs = (root: TreeNode | null): void => {
if (!root) { return }
if (root.left) { dfs(root.left) }
console.log(root.val)
arr.push(root.val)
if (root.right) { dfs(root.right) }
}
dfs(root)
for (let i = 0; i < arr.length - 1; i++) {
if (arr[i] >= arr[i+1]) {
// return false
}
}
console.log(res)
export {};在 GitHub 上查看题目所在目录:lmliheng/algorithm